We're excited to announce NeetForces Round #42 (Div. 1 + Div. 2)! The contest will take place on January 30, 2026 at 14:00 UTC.
Contest features:
Detailed video explanations for all problems from yesterday's Codeforces Round. Topics covered: DP, Binary Search, Graph Theory.
Just solved this amazing problem on AtCoder. It has a really elegant DP solution with O(nĀ²) complexity. Highly recommended for those learning dynamic programming!
We're thrilled to introduce Community Roadmaps! Now users can create and share their own learning paths with the community.
Feature Screenshot
Key features:
A comprehensive guide to segment trees with code templates in C++. Perfect for those preparing for advanced competitive programming.
class SegmentTree {
vector<int> tree;
int n;
void build(vector<int>& arr, int node, int start, int end) {
if(start == end) {
tree[node] = arr[start];
} else {
int mid = (start + end) / 2;
build(arr, 2*node, start, mid);
build(arr, 2*node+1, mid+1, end);
tree[node] = tree[2*node] + tree[2*node+1];
}
}
};Congratulations to all participants! Here are the top performers:
Thank you to all 2,847 participants! Editorial coming soon.
Prepare for ICPC, IOI, and technical interviews with our structured roadmaps and curated problem sets. Custom training available for Codeforces and AtCoder rating improvement.
#include <iostream>
#include <vector>
using namespace std;
// Sieve of Eratosthenes
vector<int> sieve(int n) {
vector<bool> is_prime(n + 1, true);
vector<int> primes;
is_prime[0] = is_prime[1] = false;
for(int i = 2; i <= n; i++) {
if(is_prime[i]) {
primes.push_back(i);
for(int j = i * i; j <= n; j += i)
is_prime[j] = false;
}
}
return primes;
}
int main() {
int n;
cin >> n;
auto primes = sieve(n);
for(int p : primes)
cout << p << " ";
return 0;
}Everything you need to excel in competitive programming
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